A particle is projected with a certain velocity at an angle theta above the horizontal from the foot of a given plane inclined at an angle of 45° to the horizontal. If the particle strike the plane normally then theta equals?
Prachi , 8 Years ago
Grade 11
1 Answers
Vikas TU
Last Activity: 8 Years ago
For particle is projected with a certain velocity at an angle theta above the horizontal is given as:
A = 45 – B/2
where
A is the angle at which it is projected from the surface of inclined plane and B is the angle of inclined plane.
here, B = 45 degree.
therefore, A = 45 -45/2 = 45/2 degree.
or 22.5 degree.
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