Grade 9Mechanics

a particle is projected vertically upwards and it reach the Maximum height H in time T sec. the height of the particle at any time t will be

Question image for a particle is projected vertically upwards and it

skusum

9 Years agoGrade 9

4 Answers

Vikas TU

9 Years ago

As the height is not depends on time , It ol depend on initial velocity and gravity

As we ol know that the maximum height ,

H_max = u²/2g

So, at any time t , the maximum height (H_maz) = u²/2g

Shreyansh Gupta

9 Years ago

We know that a certain height is reached two times in a vertical projection.(One while going upward,one while going back downward)

let the height reached in time t be h

maximum height=H

difference in height=H-h

now H is reached in T and h is reached in t time.So H-h is reached in (T-t) time ...(1)

while going back down H-h is reached in (T-t)seconds

So,

H-h=u(T-t) + ½g(T-t)²

but u =0 (velocity at max height is zero)

So,

H-h = ½g(T-t)²

h = H – ½g(T-t)² or H – ½g(t-T)²

Vaibhav srivastava

6 Years ago

V=u-gT ( at highest point v=0)

0=u-gT

U=gT

H=uT-1/2gT^2

H=uT^2-1/2gT^2

H=1/2gT^2

h=ut-1/2gt^2

h=gTt-1/2gt^2(u=gT)

H-h=1/2gT^2-gTt+1/2gt^2

H-h= 1/2g(T^2-2Tt+t^2)

h=H-1/2g(T-t)^2

Kushagra Madhukar

5 Years ago

Dear student,

Please find the solution to your problem.

V = u – gT ( at highest point v=0)

0 = u – gT

U = gT

H = uT – ½ gT²

H = uT² – ½ gT²

H = ½ gT²

Now,

h = ut – ½ gt²

h = gTt – ½ gt² (Since, u = gT)

H – h = ½ gT² – gTt + 1/2gt²

H – h = ½ g(T² – 2Tt + t²)

h = H – ½ g(T – t)²

Thanks and regards,

Kushagra

Three identical balls are placed on a frictionless horizontal surface touching each other. They stick to each other because of adhesive. Another ball of same radius and mass m is placed over the void created by the three balls. Find the forces applied by the balls kept on the floor to each other if the system remains in equilibrium.

mechanics

1 Answer Available

Last Activity: 10 Months ago

A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.

11
21
31
41

mechanics

1 Answer Available

Last Activity: 10 Months ago

A metal strip clamped at one end vibrates with a frequency of 20 Hz and amplitude of 5 mm
at the free end, where a small mass of 2 g is positioned. determine
(i) The velocity of the end when passing through the zero position
(ii) The acceleration at maximum displacement
(iii) The maximum kinetic energy of the mass

mechanics

2 Answers Available

Last Activity: 3 Years ago

An object of mass m = 0.25 kg oscillates in a fluid at the end of a vertical spring of spring
constant kH = 85 N/m, see Fig.1. The effect of the fluid resistance is governed by the
damping constant b = 0.07kg/s.
(i) Find the period of the damped oscillation.
(ii) By what percentage does the amplitude of the oscillation decrease in each cycle?

mechanics

1 Answer Available

Last Activity: 3 Years ago

If a=x² find the displacement at t =3sec if body velocity at t= 0 sec is 0

mechanics

1 Answer Available

Last Activity: 3 Years ago

View all Questions

a particle is projected vertically upwards and it reach the Maximum height H in time T sec. the height of the particle at any time t will be

skusum

4 Answers

Vikas TU

Shreyansh Gupta

Vaibhav srivastava

Kushagra Madhukar

Other Related Questions on mechanics

A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.11213141

If a=x² find the displacement at t =3sec if body velocity at t= 0 sec is 0

A car loaded with water having total mass 1000 kg moves on a straight horizontal Road starting from rest under the action of a force of 100 Newton. The water spills throw a small hole in the bottom at a rate of 0.1 KG per second the velocity of cart after 300 seconds is nearly.

11
21
31
41