a particle is projected vertically upwards and it reaches the maximum height H in T seconds. The height of particle at any time t will be?options:H-g(t-T)^2g(t-T)^2H-1/2g(t-T)^2g/2(t-T)^2

The answer should be H -1/2g(t-T)^2Consider the body falling down. As both portions of motion of body are symmetrical. It should fall a certain distance in (t-T) time( the time it takes to attain maximum height when it is at the height reached by it in time interval t). so the height above the ground is H-(distance fallen in t time interval)