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`        A particle is projected vertically upward with an initial velocity of 60m/sec find the distance and displacement by the particle in A) 6sec. B) 4secC) 8sec`
10 months ago

Vikas TU
11137 Points
```							HiiiInitial velocity = 60 m/sFinal velocity = 0m/secv = u+at So t = 6 sec S = ut + 1/2 at 2Find the distance travelled by this formula by putting value of different t and acceleration due to gravity = - 10 m/sec 2S = ut+ 1/2 at2
```
10 months ago
Khimraj
3008 Points
```							Time at which it will reach its maximum is initial velocity/g = 6 sec distance and displacement by the particle in A) 6sec. Distance = Displacement = Maximum height = ut-{1/2}gt^2 = 180m
```
10 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions