Grade 11Mechanics

A particle is projected vertically upward with an initial velocity of 60m/sec find the distance and displacement by the particle in
A) 6sec.
B) 4sec
C) 8sec

Rohan

6 Years agoGrade 11

2 Answers

Vikas TU

6 Years ago

Hiii

Initial velocity = 60 m/s

Final velocity = 0m/sec

v = u+at

So t = 6 sec

S = ut + 1/2 at 2

Find the distance travelled by this formula by putting value of different t and acceleration due to gravity = - 10 m/sec 2

S = ut+ 1/2 at2

Khimraj

6 Years ago

Time at which it will reach its maximum is initial velocity/g = 6 sec

distance and displacement by the particle in

A) 6sec.

Distance = Displacement = Maximum height = ut-{1/2}gt^2 = 180m

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A particle is projected vertically upward with an initial velocity of 60m/sec find the distance and displacement by the particle in A) 6sec. B) 4secC) 8sec

Rohan

2 Answers

Vikas TU

Khimraj

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A particle is projected vertically upward with an initial velocity of 60m/sec find the distance and displacement by the particle in
A) 6sec.
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