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Grade: 9

                        

A particle is projected vertically upward passes the same same height at 2sec and at 10 sec if acceleration due to gravity is 9.8met per sec2 then height is equal to

3 years ago

Answers : (2)

Subhash
14 Points
							
The motion under gravity is a symmetric motion therefore particle will take same time in covering same distance in upward and downward journey.
therefore if it is at a height H at first 2 sec, in upward journey, it will be at the same height H in the last 2 sec of downward jouney.
therefore, t1+t2= total time of flight
time of upward journey =(t1+t2)/2
now v=u+at
v at top most point is 0 and a is negative 
therefore, u=at
or u=9.8 X 2=58.8
now H =ut+1/2at^2
puttting t=2 and u=58.8 and a=-9.8 we get,
H=98 metres.
 
3 years ago
himanshi
11 Points
							Height covered by particle in 2sec = height covered in 10secSo,.    By S= u.t  +  1/2 (a.t)^2u.2 + 1/2 (-9.8) (2×2)  =.  u.10  +1/2 (-9.8) (10×10)2u - 19.6  =.  10u - 49010u-2u.  =490-19.68u.  = 470.4u.  =. 58.8 m/secBy putting value of `u` in  above formula2×58.8.  -1/2 ×9.8×4117.6 -19.698 m
						
3 years ago
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