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A particle is projected vertically upward passes the same same height at 2sec and at 10 sec if acceleration due to gravity is 9.8met per sec2 then height is equal to

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3 years ago

Subhash
14 Points
```							The motion under gravity is a symmetric motion therefore particle will take same time in covering same distance in upward and downward journey.therefore if it is at a height H at first 2 sec, in upward journey, it will be at the same height H in the last 2 sec of downward jouney.therefore, t1+t2= total time of flighttime of upward journey =(t1+t2)/2now v=u+atv at top most point is 0 and a is negative therefore, u=ator u=9.8 X 2=58.8now H =ut+1/2at^2puttting t=2 and u=58.8 and a=-9.8 we get,H=98 metres.
```
3 years ago
himanshi
11 Points
```							Height covered by particle in 2sec = height covered in 10secSo,.    By S= u.t  +  1/2 (a.t)^2u.2 + 1/2 (-9.8) (2×2)  =.  u.10  +1/2 (-9.8) (10×10)2u - 19.6  =.  10u - 49010u-2u.  =490-19.68u.  = 470.4u.  =. 58.8 m/secBy putting value of `u` in  above formula2×58.8.  -1/2 ×9.8×4117.6 -19.698 m
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3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions