Modern Physics> A particle is projected vertically upward...

A particle is projected vertically upward from A with a speed of 50m/s and another is dropped simultaneously from B , which is 200m vertically above A. They will cross each other after what time?

Manjeet , 6 Years ago

Grade 12th pass

2 Answers

Arun

Last Activity: 6 Years ago

Let them meet at a point h above the ground at a time t.
• Distance moved down by B in t s = (0.5gt^2) .= 200 - h
Distance moved up by A in t second is 50 t – 0.5gt^2.= h
200 = 50 t
• t = 4 s

Manjeet

Last Activity: 6 Years ago

Let h be the distance from A at which the two particles meet and t be the time taken hence that for B will be 200-h

For particle projected upward equation of motion can be given as:

h=50t+0.5gt^2

For B

-0.5gt^2 =200-h

Solving above equations

h =50t-(200-h)

0=50t-200

t=4s

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Modern Physics> A particle is projected vertically upward...

A particle is projected vertically upward from A with a speed of 50m/s and another is dropped simultaneously from B , which is 200m vertically above A. They will cross each other after what time?

Manjeet , 6 Years ago

Arun

Manjeet

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