a particle is projected vertically upward from A with a speed of 50 m/s and another is dropped simultaneously from B which is 200 m vertically above A. They cross each other ?

Question

Vishal Kumar · Answer

u1= 50m/s & u2= 0 relative speed is u1 - u2 = 50m/s . relative separation is 200m. time, t= 200/50 = 4s

Lok Nitesh · Answer

h/

Lok Nitesh · Answer

h/u = 200/50 = 4 sec as if a body thrown Vertically upwards from a height 'h’ and if another particle thrown from ground both will meet at t= h/u

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a particle is projected vertically upward from A with a speed of 50 m/s and another is dropped simultaneously from B which is 200 m vertically above A. They cross each other ?

a particle is projected vertically upward from A with a speed of 50 m/s and another is dropped simultaneously from B which is 200 m vertically above A. They cross each other ?

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a particle is projected vertically upward from A with a speed of 50 m/s and another is dropped simultaneously from B which is 200 m vertically above A. They cross each other ?

a particle is projected vertically upward from A with a speed of 50 m/s and another is dropped simultaneously from B which is 200 m vertically above A. They cross each other ?

3 Answers

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