Grade 12th passMechanics

A particle is projected upward to a maximum height H. find the time after which the ratio of potential energy to kinetic energy is 3:1

Sanju Kumar

7 Years agoGrade 12th pass

1 Answer

Arun

7 Years ago

Dear student

The total energy given to the ball when thrown is equal to $mgh$

then initially it was only $\frac{1}{2}mv^{2}$

Now by conservation of energy

$\frac{1}{2}mv^{2}=mgh=Total Energy$ …........................(1)

as KE + PE = total energy

so when the ratio is 1:3

$K.E. = \frac{1}{4} T.E.$

TE means total energy

After time t,

velocity = $v-gt$

$\frac{1}{2}m(v-gt)^{2} =\frac{1}{4}(\frac{1}{2} mv^{2})$

Solving for t we get a equation in v.

Now substitute v in terms of H from equation (1) and get the answer...

Hope it helps

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A particle is projected upward to a maximum height H. find the time after which the ratio of potential energy to kinetic energy is 3:1

Sanju Kumar

1 Answer

Arun

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