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Grade: 11
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A particle is projected up with an initial velocity of 80 feet per second the ball will be at the height of 96 feet from the ground after how much second

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3 years ago

## Answers : (1)

Deepak Kumar
31 Points
```							Initial Velovity = U0 = 80feet/second.Height = H = 80 feet.Acceleration due to gravity = g = 32 feet/s2.Using kinematic 2nd equation.   H = U0t + at2/2.  96 = 80t -32t2/2. t2 -5t +6 =0. Solving above equation We get    t = 2seconds and 3 seconds.It means when particle goes to upward direction then at 2seconds it is at 96 feet height.and at the returing time at 3seconds its height is 96feet.
```
3 years ago
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