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Grade: 11

                        

A particle is projected up with an initial velocity of 80 feet per second the ball will be at the height of 96 feet from the ground after how much second

3 years ago

Answers : (1)

Deepak Kumar
31 Points
							
Initial Velovity = U0 = 80feet/second.
Height = H = 80 feet.
Acceleration due to gravity = g = 32 feet/s2.
Using kinematic 2nd equation.
   H = U0t + at2/2.
  96 = 80t -32t2/2.
 t-5t +6 =0.
 Solving above equation We get 
   t = 2seconds and 3 seconds.
It means when particle goes to upward direction then at 2seconds it is at 96 feet height.
and at the returing time at 3seconds its height is 96feet.
3 years ago
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