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A particle is projected up with an initial velocity of 80 feet per second the ball will be at the height of 96 feet from the ground after how much second

A particle is projected up with an initial velocity of 80 feet per second the ball will be at the height of 96 feet from the ground after how much second

Grade:11

1 Answers

Deepak Kumar
31 Points
6 years ago
Initial Velovity = U0 = 80feet/second.
Height = H = 80 feet.
Acceleration due to gravity = g = 32 feet/s2.
Using kinematic 2nd equation.
   H = U0t + at2/2.
  96 = 80t -32t2/2.
 t2 -5t +6 =0.
 Solving above equation We get 
   t = 2seconds and 3 seconds.
It means when particle goes to upward direction then at 2seconds it is at 96 feet height.
and at the returing time at 3seconds its height is 96feet.

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