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A particle is projected up the inclined such that its component of velocity along the incline is 10m/s. Time of flight is 2 sec and maximum height above the incline is 5m. Then velocity of projection will be-
  1. 10m/s
  2. 10√2m/s
  3. 5√5m/s
  4. None

Dishari Das , 6 Years ago
Grade 11
anser 2 Answers
Harjot Singh

Last Activity: 6 Years ago

Use these equations
T=2uy/aaay=2
H=uuy2/aay=5
uy=velocity in y direction (here y is upward perpendicular to plane and x is along the plane)
so
UUy=velocity in y=10
 
So net speed=10$\sqrt 2$
Arun

Last Activity: 6 Years ago

 
Dear student
 
Please confirm is the answer is 10 sqrt(2) ?
 
If this is correct then I will share my solution.
 
Regards
Arun
 
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