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a particle is projected horizontally from the top of a tower with velocity 5m/s.the radius of the curvature of the path of the particle after 0.5 sec is

ananyanair1107 , 8 Years ago
Grade 11
anser 1 Answers
garima soni

Last Activity: 8 Years ago

v2/perpendicular acceleration is the formula for radius of carvature. 
v=5m/s in horizontal always.
v in vertical is .5.10=5m/s
so speed=5root2 m/s
so r=(5root2)2/10=5m
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