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Grade 11Mechanics

A particle is projected from the ground with an initial velocity of 20ms-1 at an angle of 300 with horizontal. The magnitude of change in velocity in 0.5 seconds is(g=10ms-1)

Profile image of maazhussain
8 Years agoGrade 11
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1 Answer

Profile image of Mohammad Shahbaz Shaik
8 Years ago
300 degrees is equivalent to 60 degrees with respect to negative x axis. vertical component of velocity will be 10(3)^(1/2).
v(vertical) = u – gt.
therefore net dV = (v(vertical)^2+u(horizontal)^2)^(1/2)-(u(vertical)^2-u(horizontal)^2)^(1/2)