Mechanics> A particle is projected from point A perp...

A particle is projected from point A perpendicular to inclined plane with a velocity of 50 m/s. Particle strikes a vertical plane perpendicularly at point B. Find the time taken by particle in going from point A to point B.

Rhythm Goel , 11 Years ago

Grade 11

4 Answers

Dhulipala Srikanth

as you said its is projected perprendicularly then angle becomes 90 therfore t=2usin90/g=2*50/10=10m/s

Last Activity: 11 Years ago

dilpreet

t=(50sin57)/10= 4.2s ~ 4 s

at pt b velocity becomes perpendicular i.e it is at maximum hieght so t=(usinθ)/g

from geometry θ =57 ,g=10, u=50.

Last Activity: 8 Years ago

Megha Jain

Here, u = 50 m/sec

Angle(Ѳ) = 90^o

g = 9.8 m/sec²

But practically angle is 57 degree

Then T = 2usin Ѳ/g

= 2x50x sin57/9.8

= 4.2 sec

= approx 4 sec

Last Activity: 8 Years ago

Hemant Jha

You missed angle of inclination i.e. 37° (given)

Practically angle of projection = 90-37 =53°

As it hit B perpendicularly hence B is Hmax .

Time Time taken for Hmax = usintheta/g = 50* 4/5 * 1/10 = 4 sec

Last Activity: 7 Years ago

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Mechanics> A particle is projected from point A perp...

A particle is projected from point A perpendicular to inclined plane with a velocity of 50 m/s. Particle strikes a vertical plane perpendicularly at point B. Find the time taken by particle in going from point A to point B.

Rhythm Goel , 11 Years ago

Dhulipala Srikanth

dilpreet

Megha Jain

Hemant Jha

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