A particle is projected from a point (0, 1) on Y-axis (assume + Y direction vertically upwards) aiming towards a point (4, 9). It fell on ground along x axis in 1 s. Taking g = 10 m/s² and all coordinate in metres. Find the x-coordinate where it fell.

1 (3,0)

2.(4,0)

3.(2,0)

4.(2 root2, 0)

tanΦ=9-1/4-0=2=perpendicular/base.      ...........(1)

where Φ is angle of projection

given that time of flight is 1 second

from s=ut-1/2gt²

(-1)=usinΦ(1)-1/2(10)(1)²     final displacement is -1 when it hit the ground ok!!

usinΦ=4

then

ucosΦ=usinΦ/tanΦ=4/2=2    (from equestion (1) tanΦ=2 )

then x coordinate = V_xT=(2)X(1)=2   (V_x = horizontal componant of velocity)

particle hit the ground at (2,0) OK!!!!!!!!!