×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
A particle is projected at an angle of elevation alpha and after t second it appears to have an elevation of beta as seen from the point of projection. Find the initial velocity of projection.

```
2 years ago

Arun
25359 Points
```							Dear Ishan Since there is no friction, the horizontal component of velocity will not change throught the process.so let initial velcity be u.then horizontal component = u cos α After time t, let velocity be v.Now, its horizontal compnent will be v cos ß.Since vertical velocity remains same, we get :u cos α  =   v cos ßu = v cos ß/ cos αwe have to find v.applying linear acceleration vertically.Initial vertical velocity: u sin αFinal vertical velocity =  v sin ßv sin ß = u sin α + a * tv =  (u sin α + a * t)/sin ßSubstitute this v in `u = v cos ß/ cos α ` and simplify  RegardsArun (askIITians forum expert)
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions