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Since there is no friction, the horizontal component of velocity will not change throught the process.
so let initial velcity be u.
then horizontal component = u cos α
After time t, let velocity be v.
Now, its horizontal compnent will be v cos ß.Since vertical velocity remains same, we get :
u cos α = v cos ßu = v cos ß/ cos αwe have to find v.applying linear acceleration vertically.Initial vertical velocity: u sin αFinal vertical velocity = v sin ßv sin ß = u sin α + a * tv = (u sin α + a * t)/sin ßSubstitute this v in `u = v cos ß/ cos α ` and simplify
Regards
Arun (askIITians forum expert)
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