A particle is projected at an angle 60 degrees with the horizontal with speed 10√3 m/s, from point A, as shown in the figure. At the same time, the wedge is made to move with speed 10√3m/s towards the right as shown in the figure. Then the time after which particle will strike with the wedge is?
Soumendu Majumdar , 5 Years ago
Grade 12th pass
2 Answers
Arun
Last Activity: 5 Years ago
u=Velocity of particle v=Velocity of wedge Horizontal range of projectile: R=u2sin2θ/g
=(10√3)²sin120/g
=(103√)2/g×3/√2
=150√3g
Time taken by the particle to strike the wedge:
t=R/v =150√3/g×110√3 =15/10 =1.5 s ≈ 2 s
Thus, Time taken by the particle to strike the wedge is 2 second
Soumendu Majumdar
Last Activity: 5 Years ago
The final answer is 2 sec but the process is incorrect..its a problem of relative motion and also the angle of inclination of the wedge needs some consideration. So if anyone can find another explanation do share it!
Thanks!
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