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Grade: 12th pass

                        

A particle is projected at an angle 37 with the incline plane in upward direction with 10m/s.The angle of incline plane given is53. Then the maximum distance from the incline plane attained by the particle will be?

4 years ago

Answers : (2)

Vikas TU
12154 Points
							
 the maximum distance from the incline plane attained by the particle will be:
Range maximum = u^2/g(1+ sinB)
where B = 53  degree.
put u = 10 m/s.
4 years ago
Shreyas
11 Points
							They have asked max distance from inclined place.Therefore we have to calculate Max height as range will be zero because the angle of projection is 53+37= 90°. The Max height is 3m.
						
2 years ago
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