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A particle is projected at an angle 37 with the incline plane in upward direction with 10m/s.The angle of incline plane given is53. Then the maximum distance from the incline plane attained by the particle will be?
A particle is projected at an angle 37 with the incline plane in upward direction with 10m/s.The angle of incline plane given is53. Then the maximum distance from the incline plane attained by the particle will be?

```
4 years ago

Vikas TU
14149 Points
```							 the maximum distance from the incline plane attained by the particle will be:Range maximum = u^2/g(1+ sinB)where B = 53  degree.put u = 10 m/s.
```
4 years ago
Shreyas
11 Points
```							They have asked max distance from inclined place.Therefore we have to calculate Max height as range will be zero because the angle of projection is 53+37= 90°. The Max height is 3m.
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions