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A particle is projected at an angle 37 with the incline plane in upward direction with 10m/s.The angle of incline plane given is53. Then the maximum distance from the incline plane attained by the particle will be?

A particle is projected at an angle 37 with the incline plane in upward direction with 10m/s.The angle of incline plane given is53. Then the maximum distance from the incline plane attained by the particle will be? 

Grade:12th pass

2 Answers

Vikas TU
14149 Points
7 years ago
 the maximum distance from the incline plane attained by the particle will be:
Range maximum = u^2/g(1+ sinB)
where B = 53  degree.
put u = 10 m/s.
Shreyas
11 Points
6 years ago
They have asked max distance from inclined place.Therefore we have to calculate Max height as range will be zero because the angle of projection is 53+37= 90°. The Max height is 3m.

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