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a particle is projected at an angle 30 degree with the horizontal with speed 20m/s.how high will it strike a wall 8 under root 3m away from point of projection?

nikki yadav , 7 Years ago
Grade 12
anser 2 Answers
Nitesh

Last Activity: 7 Years ago

On the basis of teacher Trajectory equationY=xtan(theta)-gx²/2u²cos²(theta)So Y=(3*1/√3) - (10*9/2*300)Y=1.58m
Subha

Last Activity: 5 Years ago

Y=tan(theta) x  --  g^2x^2/2u^2cos^2theta
Y=tan30°×8√3  --  10× (8√3) ^2/2×20^2×cos^2 30°
Y=8-3.2
Y=4.8m
This is the correct answer
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