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A particle is moving with uniform acceleration along a straight line ABC.. its velocity at A and C are 5m/s and 25m/s respectively . if BC=2AB ,find the ratio of time of travel from Ato B and B to C

luina Pani , 8 Years ago
Grade 10
anser 1 Answers
Vikas TU
Let the separation amongst An and B be x 
That is AB = x 
Speed is 5 m/sec 
At that point the normal speed =( (speed at point A)+(velocity at point C))/2 
= (5+ 25)/2 
= 15 m/sec 
Remove from A to B = x 
At that point t1 = remove/speed 
= x/15 
Separate from B to C = 2x 
At that point, t2 = separate/speed 
     t2 = 2x/15 
Proportion amongst t1 and t2 = (x/15): (2x/15) 
Last Activity: 8 Years ago
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