badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A particle is moving with uniform acc along a straight line abc . Its velocity at A n C are 5 n 25 . If bc= 2ab find tge ratio of the time of travel from A to b n fron B to c

3 years ago

Answers : (2)

Arun
24742 Points
							
Let the separation amongst An and B be x 
That is AB = x 
Speed is 5 m/sec 
At that point the normal speed =( (speed at point A)+(velocity at point C))/2 
= (5+ 25)/2 
= 15 m/sec 
Remove from A to B = x 
At that point t1 = remove/speed 
= x/15 
Separate from B to C = 2x 
At that point, t2 = separate/speed 
     t2 = 2x/15 
Proportion amongst t1 and t2 = (x/15): (2x/15) 
3 years ago
Tapish pal
21 Points
							Take a line segment AC . Now take a point B in between AC such that BC= 2AB. Now,          Speed=distance/time     So, v1= AB/t1But v1= (v+v0)/2So, (v+v0)/2=AB/t15+25/2=AB/t115=AB/t1t1=AB/15In the same wayt2=2AB/15Now,t1/t2=AB/15÷2AB/15So,   ans.--:    t1:t2=2:1
						
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details