Grade 12Mechanics

A particle is moving with a constant angular acceleration of 4 rad /s^2 in a circular path. At time t =0, particle was at rest. Find the time at which the magnitudes of centripetal acceleration and tangential acceleration are equal.

Aoishi

9 Years agoGrade 12

1 Answer

Vikas TU

9 Years ago

Dear Student,

As we realize that

Centripetal speeding up = v^2/r

To start with condition of movement

ω = ωo+ αt

As beginning rakish speed is 0

ω = αt

v/r = 4t

v = 4tr.

Extraneous increasing speed = centripetal quickening

αr = a

4r = v^2/r

4r = (4tr)2/r

4 = 16t^2

t = ½

t = 0.5 sec.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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A particle is moving with a constant angular acceleration of 4 rad /s^2 in a circular path. At time t =0, particle was at rest. Find the time at which the magnitudes of centripetal acceleration and tangential acceleration are equal.

Aoishi

1 Answer

Vikas TU

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