A particle is moving in the +X direction with its velocityV=ax^1/2 [a is constant] .Assume that at t=0,the particle was located at X=0 then the value of time dependence of velocity
Sayam Bandyopadhyay , 7 Years ago
Grade 11
1 Answers
deepak
Last Activity: 7 Years ago
v=ax^1/2
then,
dx/dt=v=a(x^1/2)
dx/(x^1/2)=a(dt)
on intergrating , we get ,
2(x^1/2)=at+c
since at t=0 => x=0 => c=0
therefore,
2(x^1/2)=at
subs, in the first eqn,
v=a(at)/2
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