Mechanics> A particle is moving along the straight l...

A particle is moving along the straight line with an initial velocity 48m/sec and acceleration -10m/sec² .the distance traveled by particle in 5^th second

Ayush kumar , 8 Years ago

Grade 11

2 Answers

Gowtham

formula for the distance travelled by a body in nth second is S_n=u+a/2(2n-1)

n=5

intial velocity u=48

it is retarding so a

s5=3m

Last Activity: 8 Years ago

FUN BLASTER

In this question firstly we will check at which instant velocity of particle become zero

u=48m/s

a=-10m/s²

v=u+at

0=48-10×t

t=4.8s

This is in between our 5th sec.

So firstly find distance till 4.8s than subtract from distance till 4sec .

Till 4.8seconds

v²=u²+2as

0=(48)²-10s

S=115.2m

Till 4 sec

S=ut+1/2at²

S=48×4-1/2×10×4²

S=112

Distance 4.8s-4sec = 115.2-112=3.2m = distance from starting of 5th sec till 4.8s

Now we find distance in remaining 0.2sec from 5sec

t=0.2sec

u=0

a=+10m/s

S=48(0.2)+1/2×10×(0.2)²

S=0.2m

At last total distance in 5th sec = distance from starting of 5th sec till 4.8s + distance of remaining 0.2s

= 3.2+0.2m=17/5m

Last Activity: 4 Years ago

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Mechanics> A particle is moving along the straight l...

A particle is moving along the straight line with an initial velocity 48m/sec and acceleration -10m/sec2 .the distance traveled by particle in 5th second

Ayush kumar , 8 Years ago

Gowtham

FUN BLASTER

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