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A Particle is moving along the circle x 2 +y 2 =a 2 in anticlockwise direction. The x-y plane is a rough horizontal stationary surface. At the point (acos(th), asin(th)), The unit vector in the direction of friction on the particle is: coso i ^ + sino j ^ - [ coso i^ + sino j^] sino i^ – coso j^ coso i^ – sino j^ Along with proper explaination. thanks
A Particle is moving along the circle x2+y2=a2 in anticlockwise direction. The x-y plane is a rough horizontal stationary surface. At the point (acos(th), asin(th)), The unit vector in the direction of friction on the particle is:	coso i^ + sino j^	- [ coso i^ + sino j^]	sino i^ – coso j^	coso i^ – sino j^Along with proper explaination. thanks

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4 years ago

Vikas TU
14149 Points
```							Put (acos(th), asin(th) in the circle eqn. and solve for thetha in differnetial of x2+y2=a2 Thus given, x2+y2=a22x + 2ydy/dx = 0at  (acos(th), asin(th)),Get dy/dx .i.e v and then write a = v^2/af = uma=>
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4 years ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions