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A particle is moving along a straight line such that its acceleration can be given as a=3-4t, where t is in second. At t=0, its velocity is v=2m/s. Distance travelled by particle in 3 s is
a = 3 -4tHence dv = a.dtdv = (3-4t) dtOn integratingv = 3t - 2t² +cBut at t= 0, v =2 henceC = 2Nowds = v dtOn integratingS = -(2/3)t³ +(3/2) t² +2tHenceDistance travelled in 3 secput t = 3S = -18 +13.5 +6S = 1.5 m
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