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A particle is executing SHM. If its amplitude is 2m and periodic time 2 seconds. Then calculate the meximum velocity of the particle


3 years ago

Shailendra Kumar Sharma
188 Points
							 The maximum velocity is \omega A Where \omega is angular velocity $\omega =\frac{2\Pi }{T}$ Since T=2 secThus $\omega =\Pi$  and given Amplitude A=2so maxium velocity will be 2$\Pi$ m/s

3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions