Grade 12Mechanics

A particle is dropped from height 100m and another particle is projected vertically upward with velocity 50m/s from the ground along the same line.find out the position where two particle will meet

Abigail Treasa

7 Years agoGrade 12

2 Answers

Ram agrawal

7 Years ago

I'm doing this ques with the concept of relative motion

Let us consider dropped particle A and upward thrown particle B.(suppose u are a insect and sitting on B , now B will be at rest for u)

Ram agrawal

7 Years ago

Now ,

V_ab= V_a-V_{b (velocity of A w.r.t B)}

(while sitting on A seeing B is Vab)

V_ab= 0-50 = -50m/s

a_ab= -g-(-g) =0 ( acceleration of A w.r.t B)

Distance=100m (as time and distance between 2 particle are independent of frame)

Now , since a = 0 it is a simple non-accelerated motion.

Applying ,

Speed=distance/time

50=100/t

=>time=2 sec

Now, we can calculate distance travelled by A in time=2sec , that is at which height they will meet.)

=>S=ut+at²/2 ( 2^nd equation of motion)

=>S=(0)(2)-(10)(2)²/2

=>S=-20m ( negative sign signifies direction)

So, the particles will meet 20m from top or 30m above ground.

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A particle is dropped from height 100m and another particle is projected vertically upward with velocity 50m/s from the ground along the same line.find out the position where two particle will meet

Abigail Treasa

2 Answers

Ram agrawal

Ram agrawal

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