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A particle is describing uniform circular motion in the anticlockwise sense such that it's time period of revolution is T. At t equal to zero the particle is observed to be at A. if theta 1 be the angle between acceleration at t equal to T by 4 and average velocity in the time interval 0 to T by 4 and theta 2 be the angle between acceleration at t equal to T by 4 and the change in velocity in the time interval 0 to T by 4 then: 1.theta 1= 135° . theta 2 =45° 2. ,,. =135°. ,, . =135° 3. ,,. =45°. ,,. =135° 4. ,,. =45° . ,,. =45°

A particle is describing uniform circular motion in the anticlockwise sense such that it's time period of revolution is T. At t equal to zero the particle is observed to be at A. if theta 1 be the angle between acceleration at t equal to T by 4 and average velocity in the time interval 0 to T by 4 and theta 2 be the angle between acceleration at t equal to T by  4 and the change in velocity in the time interval 0 to T by 4 then:
1.theta1=135° .  theta2 =45°
2.     ,,.    =135°.       ,, .    =135°
3.      ,,.    =45°.        ,,.       =135°
4.       ,,.    =45° .      ,,.        =45°

Grade:11

1 Answers

Arun
25750 Points
5 years ago
here Vavg = displacement/time ... as time is a scalar and others are vectors.. their direction is same... now displacement and acceleration make an angle of 135 degrees..... (by using angle between vectors..) now change in velocity is V2-V1 ... here V2 & V1 have same magnitude but r perpendicular... hence V2-V1 makes 45 degrees with V2 , which is perpendicular to acc. hence angle b/w V2-V1 & acc. is 45 degrees

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