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A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane. It follows that :a) its velocity is constantb) its acceleration is constantc) its kinetic energy is constantd) it moves in a circular path.
As no force is acting in direction of velocity.. there would b no change in velocity.. a) is correctAlso it moves in circular path.. d)ThanksBHARAT BAJAJAskiitians faculty
F=mrw^2F=mv^2/rNow F IS CONSTANTThus,mv^2/r is constantNow r will be constant Thus mv^2 is constantThis implies Kinetic energy I.e. mv^2/2 is also constantHere velocity and acceleration will not be constant since velocity is a vector quantity and in a circular motion velocity will keep changing
A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane. It follows that :c) its kinetic energy is constant
If a force of constant magnitude which is always perpendicular to the velocity of the particle acts on a particle,the work done and hence the change in kinetic energy will be zero, therefore option (c) Kinetic energy is constant, is the correct option.
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