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A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane. It follows that :a) its velocity is constantb) its acceleration is constantc) its kinetic energy is constantd) it moves in a circular path.

satendra , 10 Years ago

Grade 12th pass

5 Answers

bharat bajaj

Last Activity: 10 Years ago

As no force is acting in direction of velocity.. there would b no change in velocity.. a) is correct

Also it moves in circular path.. d)

Thanks

BHARAT BAJAJ

Askiitians faculty

Unknown

Last Activity: 7 Years ago

F=mrw^2F=mv^2/rNow F IS CONSTANTThus,mv^2/r is constantNow r will be constant Thus mv^2 is constantThis implies Kinetic energy I.e. mv^2/2 is also constantHere velocity and acceleration will not be constant since velocity is a vector quantity and in a circular motion velocity will keep changing

Sonia

Last Activity: 7 Years ago

A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane. It follows that :c) its kinetic energy is constant

Monalisha Mohanty

Last Activity: 6 Years ago

If a force of constant magnitude which is always perpendicular to the velocity of the particle acts on a particle,the work done and hence the change in kinetic energy will be zero, therefore option (c) Kinetic energy is constant, is the correct option.

Yashika Kothari

Last Activity: 6 Years ago

Dear User

In Uniform circular motion,magnitude of velocity i.e. speed is constant.

Velocity changes as the direction varies at every instant. And yes it moves in a circular path. So kinetic energy is constant. As magnitude remains constant. So the correct options are (c)and(d)