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A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane. It follows that : a) its velocity is constant b) its acceleration is constant c) its kinetic energy is constant d) it moves in a circular path.

```
6 years ago

bharat bajaj
IIT Delhi
122 Points
```							As no force is acting in direction of velocity.. there would b no change in velocity.. a) is correctAlso it moves in circular path.. d)ThanksBHARAT BAJAJAskiitians faculty
```
6 years ago
Unknown
13 Points
```							F=mrw^2F=mv^2/rNow F IS CONSTANTThus,mv^2/r is constantNow r will be constant Thus mv^2 is constantThis implies Kinetic energy I.e. mv^2/2 is also constantHere velocity and acceleration will not be constant since velocity is a vector quantity and in a circular motion velocity will keep changing
```
3 years ago
Sonia
12 Points
```							A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane. It follows that :c) its kinetic energy is constant
```
3 years ago
Monalisha Mohanty
13 Points
```							If a force of constant magnitude which is always perpendicular to the velocity of the particle acts on a particle,the work done and hence the change in kinetic energy will be zero, therefore option (c) Kinetic energy is constant, is the correct option.
```
2 years ago
Yashika Kothari
19 Points
```							Dear UserIn Uniform circular motion,magnitude of velocity i.e. speed is constant.Velocity changes as the direction varies at every instant. And yes it moves in a circular path. So kinetic energy is constant. As magnitude remains constant. So the correct options are (c)and(d)
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions