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a particle initially at rest,start moving in a straight line with an acceleration a=6t+4m/S^.The distance covered by it in 3s is

Shubham , 7 Years ago
Grade 11
anser 1 Answers
Santhosh

Last Activity: 7 Years ago

On integrating once we get v=3t^2+4t+c. To find c put at t=o v=o because starts fron rest and again integrating s=t^3+2t^2 sub t=3we get 45mts

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