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Grade 11Mechanics

A particle begins to move with a initial velocity oo of 2m/s and continues to move in a line with a constant acceleration a in the direction of velocity. Ten seconds later a second particle begins to move from the same point wiwi an initial velocity of 12m/s in the same direction with the same acceleration. The maximum vaval of a so that it is possible for the second particle to hit the first assuming the two particles traveled for sufficiently long, is
A. 1m/s^2
B. 0.5m/s^2
C. 0.8m/s^2
D. 0.6m/s^2

Profile image of Sri laasya
8 Years agoGrade 11
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1 Answer

Profile image of Karan Gupta
ApprovedApproved Tutor Answer8 Years ago
Since acceleration is same for both: Once the second particle starts, relative velocity will remain constant for the particles.
Hence, the velocity of first particle should attain a maximum equal to 12 m/s before the second particle may start, in order that it can catch the first particle.
Hence, 12 = 2 + 10*a
means a = 1 m/s^2 Option A