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A particle accelerates from rest at a constant rate for sometime and attains a velocity of 8 metre per second afterwards It deaccelerates at constant rate and comes to rest if the total time taken is 4 second the distance travelled is

Akshay keshwani , 7 Years ago
Grade 11
anser 1 Answers
Venkat
If you draw a grpah of the problem, a triangle will be formed with base as total time taken = t1+t2
time for acceleration t1
time for deceleration t2
 
The height will the maximum velocity.
 
Area of the triangle is the distance travelled, so
 
s = 0.5vt = 0.5*8*4 = 16 m
Last Activity: 7 Years ago
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