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```
A particle A moves along the line y = d (30 m) with a constant velocity (v= 3.0 m/s) directed parallel to the positive x axis (Fig. 4-40). A second particle B starts at the origin with zero speed and constant acceleration (a = 0.40 m/s2) at the same instant that particle A passes the y axis. What angle θ between and the positive y axis would result in a collision between these two particles?
A particle A moves along the line y = d (30 m) with a constant velocity  (v= 3.0 m/s) directed parallel to the positive x axis (Fig. 4-40). A second particle B starts at the origin with zero speed and constant acceleration  (a = 0.40 m/s2) at the same instant that particle A passes the y axis. What angle θ between  and the positive y axis would result in a collision between these two particles?

```
5 years ago

396 Points
```							The negative value of t1 can be ignored to haveTherefore, the collision occurs after 12.2 s .
```
5 years ago
ankit singh
609 Points
```							The component of velocity of B along x and y-directions:VBX​=20cos60o=20×21​=10 m/sVBY​=20sin60=2023​​=203​ m/s And, VA​=10i^VB​=10i^+103​j^​VBA​=VB​−VA​=10i^+103​j^​−10i^=103​j^​
```
5 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions