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A particle A moves along the line y = d (30 m) with a constant velocity (v= 3.0 m/s) directed parallel to the positive x axis (Fig. 4-40). A second particle B starts at the origin with zero speed and constant acceleration (a = 0.40 m/s2) at the same instant that particle A passes the y axis. What angle θ between and the positive y axis would result in a collision between these two particles?

A particle A moves along the line y = d (30 m) with a constant velocity  (v= 3.0 m/s) directed parallel to the positive x axis (Fig. 4-40). A second particle B starts at the origin with zero speed and constant acceleration  (a = 0.40 m/s2) at the same instant that particle A passes the y axis. What angle θ between  and the positive y axis would result in a collision between these two particles?

Grade:11

2 Answers

Aditi Chauhan
askIITians Faculty 396 Points
8 years ago
236-410_1.PNG
The negative value of t1 can be ignored to have
236-1667_1.PNG
Therefore, the collision occurs after 12.2 s .
236-1282_1.PNG
ankit singh
askIITians Faculty 614 Points
3 years ago

The component of velocity of B along x and y-directions:
VBX​=20cos60o=20×21​=10 m/s

VBY​=20sin60=2023​​=203​ m/s 
And, VA​=10i^
VB​=10i^+103​j^​
VBA​=VB​−VA​=10i^+103​j^​−10i^=103​j^​

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