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`        A particle A is moving with a constant velocity of 10 m/sec. Another particle B is moving with a constant but unknown velocity. At an instant, the line joining A and B  makes an angle of 30 dgree with velocity of A. Find the minimum possible magnitude of velocity of B. If they collide after some time.`
one year ago

Khimraj
3008 Points
```							 Let VB makes angle 'x' with the line joining A & B.Then component of both velocities perpendicular to line AB must be equal if they are to meet(collide).VB Sinx = VA Sin(30degree) = 10*1/2 = 5VB to be min. Sinx must be max. as their product is a constant.So max(Sinx)=1VB = 5 m/sHere it simply uses the fact that minimum distance of a point from a given line is perpendicular from that point to that line.
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions