a partical droped from the heighest place of a building. in the final second the particle moved half height of the bulding . what is the height of the building?
Zamrin jameel , 10 Years ago
Grade 12
1 Answers
Sher Mohammad
Last Activity: 10 Years ago
distance travelled in n seconds, s = 5n^2 v= 10(n-1) s’= 10(n-1)+ 5 (n-1)^2 s-s’= s/2= 5n^2- 10n+10-5n^2+10n-5= 5= s/2 s=10
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