0

Guest

Courses New

a partical droped from the heighest place of a building. in the final second the particle moved half height of the bulding . what is the height of the building?

a partical droped from the heighest place of a building. in the final second the particle moved half height of the bulding . what is the height of the building?

Grade:12

1 Answers

Sher Mohammad IIT Delhi
askIITians Faculty 174 Points
9 years ago

distance travelled in n seconds, s = 5n^2
v= 10(n-1)
s’= 10(n-1)+ 5 (n-1)^2
s-s’= s/2= 5n^2- 10n+10-5n^2+10n-5= 5= s/2
s=10

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More