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A paricle starts from origin . Moves under the potential field of U = x^2 -3x . Then kinetic energy at x = 2

Ashish , 5 Years ago
Grade 12
anser 1 Answers
Vikas TU

Last Activity: 5 Years ago

Hiii 
F= - dU / dx = -(2x -3) 
mvdv /dx = (3-2x) 
v^2 /2 = 3x - x^2 
v at X = 2 = 4 
KE = 1/2 mv^2 = 8 joule
 
 

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