A paricle is projected from a point whose perpendicular distance from a plane inclined at an angle of 60 degrees with the horizontal is dm.find the maximum speed at which the particle has to be thrown so as to strike the inclined lane normally.

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ROSHAN MUJEEB · Answer

x=2gu2​=2&times;10102​=5m Ashis the perpendicular distance from the incline plane sin37o=53​ or,xh​=53​ &there4;h=53​&times;x=53​&times;5=3m Here range on inclined plane will be zero, as particle goes vertically upand comes back.

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A paricle is projected from a point whose perpendicular distance from a plane inclined at an angle of 60 degrees with the horizontal is dm.find the maximum speed at which the particle has to be thrown so as to strike the inclined lane normally.

A paricle is projected from a point whose perpendicular distance from a plane inclined at an angle of 60 degrees with the horizontal is dm.find the maximum speed at which the particle has to be thrown so as to strike the inclined lane normally.

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A paricle is projected from a point whose perpendicular distance from a plane inclined at an angle of 60 degrees with the horizontal is dm.find the maximum speed at which the particle has to be thrown so as to strike the inclined lane normally.

A paricle is projected from a point whose perpendicular distance from a plane inclined at an angle of 60 degrees with the horizontal is dm.find the maximum speed at which the particle has to be thrown so as to strike the inclined lane normally.

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