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A parabolic path of a projectile is y=x/(3^0.5) – (x^2)/60. It’s maximum height is

A parabolic path of a projectile is y=x/(3^0.5) – (x^2)/60.
It’s maximum height is 

Grade:11

1 Answers

Abhishek Pachauri
35 Points
9 years ago
the answer is 5m. ther are two ways two solve this problem.first apply maxima minima and find out the value of x which is 30/3^0.5.put it in the given eq. and get y.  the second method is using equation of projectile.

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