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A parabolic path of a projectile is y=x/(3^0.5) – (x^2)/60.It’s maximum height is

Shinnu , 10 Years ago
Grade 11
anser 1 Answers
Abhishek Pachauri

Last Activity: 10 Years ago

the answer is 5m. ther are two ways two solve this problem.first apply maxima minima and find out the value of x which is 30/3^0.5.put it in the given eq. and get y.  the second method is using equation of projectile.

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