a packet is released from a balloon accelerating upward with acceleration a. the acceleration of packet just after the release is

Just after the release the packet posses only the component of the velocity aquired. Here the accleration of the balloon has no effect on the acceration of the body. When the body is released, it is under free fall, under the effect of gravitational force exerted by earth. Hence the acceleration of the body is equal to g towards the centre of earth.

Since the ballon was moving upward with acceleration a, there is a force of gravity on the packet too. The balloon is moving upward bexause the reaction force R>W, weight of the packet. As long as the packet was attached with the balloon, the packet acquired the velocity of the balloon, as the same force is acting on both of them. But as soon as the packet is released, the reaction force no longer acts on the packet, it is under free fall, under the influence of only gravitational force (neglecting viscous drag). So the acceleration of the packet becomes g.You can also relate is to a lift moving upward with acceleration a. If suddenly the strong is cut, it falls freely and its acceleration is g.Thanks for asking again.If you have any further doubt, you can re-post.THANKS

hi Dhany

The accleration of the packet will be `g` acting downward as no external force other then gravity working on it.it will achieve the case of free fall. If I am wrong please ..explain the right answet

acceleration due to gravity =g.Because as soon as the packet droped from ballon,it looses contact of balloon.It is under free fall now.There fore it occurs the acceleration due to gravity.