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question mark

a nuetron moving with constant speed passes two points 3.6m apart in 1.8*10^-4 s. the kinetic energy of the nuetron is
​1). 2.1*10^3eV
​2) 2.1 eV
3) 21eV
4) 2.1*10^-3 eV

gurnoor kaur , 7 Years ago
Grade 9
anser 1 Answers
Arun
Dear student
 
V = 3.6/(1.8* 10^-4) = 2 * 10^4 m/sec
 
K.E. = ½ *m * v² = ½ * 1.67* 10^-27 * (2*10^4)²
 
 = 3.34 * 10^-19 joules = 2.1 eV
 
 
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Last Activity: 7 Years ago
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