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Grade 12th passMechanics

A non- viscous liquid of constant density 1000 Kg/m3 flows in a streamline motion along a tube of variable cross section. The tube is kept inclined in the vertical plane as shown in the figure. The area of cross-section of the tube at two points P and Q at heights of 2 meters and 5 meters are respectively m2 and . The velocity of the liquid at point P is . Find the work done per unit volume by the pressure and the gravity forces as the fluid flows from point to .

Profile image of Manish chaturvedi
9 Years agoGrade 12th pass
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

To solve the problem of calculating the work done per unit volume by pressure and gravitational forces as a non-viscous liquid flows through a tube of variable cross-section, we can apply the principles of fluid dynamics, specifically Bernoulli's equation and the concept of gravitational potential energy. Let's break this down step by step.

Understanding the Problem

We have a liquid flowing through a tube that is inclined at an angle, with two points of interest: P and Q. The heights at these points are given as 2 meters and 5 meters, respectively. The density of the liquid is constant at 1000 kg/m³, and we need to find the work done per unit volume by the pressure and gravity forces as the fluid moves from point P to point Q.

Key Concepts

  • Bernoulli's Equation: This principle states that for an incompressible, non-viscous fluid flowing in a streamline motion, the total mechanical energy along a streamline is constant. It can be expressed as:
    P + 0.5ρv² + ρgh = constant
    where P is the pressure, ρ is the density, v is the velocity, g is the acceleration due to gravity, and h is the height.
  • Work Done by Forces: The work done per unit volume by pressure and gravitational forces can be derived from the changes in pressure and potential energy as the fluid moves between the two points.

Applying Bernoulli's Equation

Let's denote the variables at point P as follows:

  • Height (h₁) = 2 m
  • Velocity (v₁) = velocity at point P
  • Pressure (P₁) = pressure at point P

At point Q, we have:

  • Height (h₂) = 5 m
  • Velocity (v₂) = velocity at point Q
  • Pressure (P₂) = pressure at point Q

According to Bernoulli's equation, we can write:

P₁ + 0.5ρv₁² + ρgh₁ = P₂ + 0.5ρv₂² + ρgh₂

Calculating Work Done

The work done per unit volume by the pressure forces can be expressed as the change in pressure, while the work done by gravity can be expressed as the change in potential energy per unit volume. Thus, we can express the total work done per unit volume as:

W = (P₁ - P₂) + ρg(h₁ - h₂)

Substituting the heights:

W = (P₁ - P₂) + ρg(2 - 5) = (P₁ - P₂) - 3ρg

Final Steps

To find the specific values, we would need the pressures at points P and Q, as well as the velocity at point P. However, we can conclude that the work done per unit volume will depend on the difference in pressure and the gravitational potential energy change due to the height difference.

In summary, the work done per unit volume by the pressure and gravity forces as the fluid flows from point P to point Q can be calculated using the derived formula. If you have specific values for the pressures or velocities, we can plug those in to get a numerical answer.