A motor rotating at 500 rpm is switched off. It comes to rest in 10 seconds. Find the angular retardation and the number of revolutions made by it before stopping.
Adil Majeed , 10 Years ago
Grade 11
1 Answers
Shobhit Varshney
Last Activity: 10 Years ago
Hi,
Given , wo= 500 rpm = 500 /60 rotations per second = 25/3 rps time = 10 seconds
So, w = 0 = wo+t, = – 25/ 30 rotations / s2= -5/6 rotations / s2
Now,= wo t+ 0.5t2
So,= (25/3) 10 + 0.5 (-5/6) 102= 125/3 rotations.
thanks
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