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A motor rotating at 500 rpm is switched off. It comes to rest in 10 seconds. Find the angular retardation and the number of revolutions made by it before stopping.

Adil Majeed , 10 Years ago
Grade 11
anser 1 Answers
Shobhit Varshney

Last Activity: 10 Years ago

Hi,

Given , wo= 500 rpm = 500 /60 rotations per second = 25/3 rps
time = 10 seconds

So, w = 0 = wo+\alphat,
\alpha= – 25/ 30 rotations / s2= -5/6 rotations / s2

Now,\Theta= wo t+ 0.5\alphat2

So,\Theta= (25/3) 10 + 0.5 (-5/6) 102= 125/3 rotations.

thanks

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