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A metallic chain 1m long lies on a horizontal surface of a table. The chain starts sliding on the table if 25cm hangs over the edge of a table. The correct value of the coefficient of friction between the table and the chain is1/3 2/3 1/4 1/5
let m be the mass for 1 m length chain then 25 cm length the mass would be: = > m/4balacncing the forces we get,f = mg/4.u*(3m/4)*g = mg/4u= 1/3
Let us consider [m] as the mass foe 1m length chain.Then 25 cm length would have mass ¼th of the total mass . So, mass for 25 cm is m/4 . By balancing the forces f=mg/4we know that f=u[mue]nu*[3m/4]*g=mg/4.By solving we get u*=1/3
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