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Grade 9Electric Current

A mechanism with 2 sliders is shown in the fig. Slider A at the instant shown has a speed of 3 m/sec and is accelerating at the rate of 15 m/s^2 towards rite at the given instant . If rod AB has a length of 3m and [tex] heta [/tex] is 60 degree at the instant shown. Find angular acceleration of the rod.

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Profile image of Jitender Pal
12 Years agoGrade 9
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

To determine the angular acceleration of rod AB in the given mechanism, we can use the relationship between linear acceleration and angular acceleration. The key here is to analyze the motion of the sliders and how it relates to the rotation of the rod.

Understanding the Setup

We have a mechanism with two sliders, and at the instant described, Slider A is moving with a speed of 3 m/s and accelerating at 15 m/s² towards the right. The rod AB has a length of 3 m, and the angle θ is 60 degrees. The goal is to find the angular acceleration of rod AB.

Key Concepts

Angular acceleration (α) can be related to the linear acceleration (a) of a point on the rod using the formula:

  • a = r * α

Where:

  • a is the linear acceleration of the point on the rod.
  • r is the distance from the pivot point to the point where the linear acceleration is measured (in this case, the length of the rod).
  • α is the angular acceleration.

Calculating Linear Acceleration at Point B

Since Slider A is moving and accelerating, we need to find the linear acceleration at point B, which is at the end of rod AB. The acceleration of Slider A contributes to the acceleration of point B. The linear acceleration of point B can be found using the angle θ:

  • The horizontal component of the acceleration at point B is given by: a_B = a_A * cos(θ)
  • The vertical component of the acceleration at point B is given by: a_B = a_A * sin(θ)

Given that the acceleration of Slider A (a_A) is 15 m/s² and θ is 60 degrees, we can calculate the components:

  • a_Bx = 15 * cos(60°) = 15 * 0.5 = 7.5 m/s²
  • a_By = 15 * sin(60°) = 15 * (√3/2) ≈ 12.99 m/s²

Finding the Resultant Acceleration

The resultant linear acceleration at point B can be found using the Pythagorean theorem:

  • a_B = √(a_Bx² + a_By²)

Substituting the values:

  • a_B = √((7.5)² + (12.99)²) ≈ √(56.25 + 168.68) ≈ √224.93 ≈ 15 m/s²

Calculating Angular Acceleration

Now that we have the linear acceleration at point B, we can find the angular acceleration using the formula:

  • α = a_B / r

Here, r is the length of the rod, which is 3 m:

  • α = 15 m/s² / 3 m = 5 rad/s²

Final Result

The angular acceleration of rod AB at the given instant is 5 rad/s². This value indicates how quickly the rod is changing its angular velocity due to the motion of Slider A.