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A mass of M kg is suspended to a weightless string.Find the horizontal force that is required to displace it until it makes an an angle 45 degree with initial vertical direction.

Subodh Barthwal , 10 Years ago
Grade 11
anser 4 Answers
Ashish Kumar

Last Activity: 10 Years ago

The work done by the force will be equal to the potentail energy gained by the mass.

Let L be the length of the string ,
F.d= MgL (1 -cos45 )
The horizontal displacement of the mass is d= L sin 45
F L sin45 = Mg L(1 - 45)
F = Mg (sq. root 2 - 1)



169-2327_signature.GIF

Lokesh

Last Activity: 10 Years ago

USE CONSERVATION OF ENERGY

shraman

Last Activity: 7 Years ago

Let x be the force required
T Sin 45=M kg   …....1
T Cos45=x    ….......2
Divide equation 1 and 2,
1=M/x
x=M

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the solution to your problem attached herewith.
 
The work done by the force will be equal to the potentail energy gained by the mass.
Let L be the length of the string ,
F.d= MgL(1 – cos45)
The horizontal displacement of the mass is d = Lsin45
FLsin45 = MgL(1 – cos45)
F = (2 - 1)Mg
 
Hope it helps.
Thanks and regards,
Kushagra

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