A mass of 100gm is attached to the end of a rubber string 49cm and area of cross section 20mmsstring is whirled round,horizontally at a speed of 40rps in a circle of radius 51cm. Find young`s modulus of the rubber?
Briji , 7 Years ago
Grade 11
1 Answers
Arun
Last Activity: 7 Years ago
Given that,
L = 49 cm
l = 51 - 49 = 2 cm
Cross sectional area a 20 mm2 = 0.2 cm2
m = 100 g
R = 51 cm
ω = 40 r.p.s = 80 π rad s-1
When the mass attached to the string is whirled, the length of the string increases under the effect of centrifugal force.
The centrifugal force F = mRω2
= 100 x 51 x (80 π)2
Now put
Y = FL/Al
And gou will get Young's modulus
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