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A mass of 100gm is attached to the end of a rubber string 49cm and area of cross section 20mms string is whirled round,horizontally at a speed of 40rps in a circle of radius 51cm. Find young`s modulus of the rubber?
A mass of 100gm is attached to the end of a rubber string 49cm and area of cross section 20mms  string is whirled round,horizontally at a speed of 40rps in a circle of radius 51cm. Find young`s modulus of the rubber?

```
3 years ago

Arun
25768 Points
```							Given that, L = 49 cml = 51 - 49 = 2 cmCross sectional area a  20 mm2 = 0.2 cm2m = 100 gR = 51 cmω = 40 r.p.s = 80 π rad s-1 When the mass attached to the string is whirled, the length of the string increases under the effect of centrifugal force. The centrifugal force F = mRω2                                = 100 x 51 x (80 π)2 Now putY = FL/AlAnd gou will get Young's modulus
```
3 years ago
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• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions