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A mass of 100gm is attached to the end of a rubber string 49cm and area of cross section 20mms string is whirled round,horizontally at a speed of 40rps in a circle of radius 51cm. Find young`s modulus of the rubber?

A mass of 100gm is attached to the end of a rubber string 49cm and area of cross section 20mms string is whirled round,horizontally at a speed of 40rps in a circle of radius 51cm. Find young`s modulus of the rubber?

Grade:11

1 Answers

Arun
25750 Points
6 years ago
Given that,
 
L = 49 cm
l = 51 - 49 = 2 cm
Cross sectional area a  20 mm2 = 0.2 cm2
m = 100 g
R = 51 cm
ω = 40 r.p.s = 80 π rad s-1
 
When the mass attached to the string is whirled, the length of the string increases under the effect of centrifugal force.
 
The centrifugal force F = mRω2
                                = 100 x 51 x (80 π)2
 
Now put
Y = FL/Al
And gou will get Young's modulus
 

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