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# A mass of 1 kg is placed at (1m, 2m, 0). Another mass of 2 kg is placed at (3m, 4m, 0). Find moment of inertia of the system about z-axis.(A) 50 kg-m2.                       (B) 55 kg-m2(C) 60 kg-m2.                         (D) 65 kg-m2

Khimraj
3007 Points
2 years ago
m1 = 1kgr1 = m2 =
Khimraj
3007 Points
2 years ago
m1 = 1kg
r1 = $\sqrt{1^{2} + 2^{2}} = \sqrt{5}$
m2 = 2kg
r2 = $\sqrt{3^{2} + 4^{2}} = 5$
I = m1*r12 + m2*r22 = 55 kg-m2
Hope it clears...................................
Sarang
38 Points
2 years ago
m1 = mass of obj 1
m2= mass of obj 2

m1 = 1kg

r1 = $\sqrt{1^{2} + 2^{2}} = \sqrt{5}$
so,

m2 = 2kg

r2 = $\sqrt{3^{2} + 4^{2}} = 5$
hence,

I0 = m1*r12 + m2*r22
= 55 kg-m2

Regards
sarang