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Grade: 10
        
A mass of 1 kg is placed at (1m, 2m, 0). Another mass of 2 kg is placed at (3m, 4m, 0). Find moment of inertia of the system about z-axis.
(A) 50 kg-m2.                       (B) 55 kg-m2
(C) 60 kg-m2.                         (D) 65 kg-m2
 
 
10 months ago

Answers : (3)

Khimraj
2873 Points
							m1 = 1kgr1 = m2 =
						
10 months ago
Khimraj
2873 Points
							
m1 = 1kg
r1 = \sqrt{1^{2} + 2^{2}} = \sqrt{5}
m2 = 2kg
r2 = \sqrt{3^{2} + 4^{2}} = 5
I = m1*r12 + m2*r22 = 55 kg-m2
Hope it clears...................................
10 months ago
Sarang
38 Points
							
m1 = mass of obj 1
m2= mass of obj 2
 
m1 = 1kg
 
r1 = \sqrt{1^{2} + 2^{2}} = \sqrt{5}
so,
 
m2 = 2kg
 
r2 = \sqrt{3^{2} + 4^{2}} = 5
hence, 
 
I0 = m1*r12 + m2*r22 
= 55 kg-m2
 
Regards
sarang
6 months ago
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