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`        A mass mkg is suspended by a weightless string of length l a horizontal force is applied to displace it slowly until the string makes 30degree with the initial vertical direction what is the work done by applied force?`
2 years ago

Diwankar singh
14 Points
```							Mass=m,length=l.                                        Work done=Force*distance.                                Force=mass*acceleration                                    =m*g.      --------(1)                                                                 Cos30°=b/h where,h=length of string=l and b=displacement=?                                            Cos30°=b/l        Cos30°=√3/2Therefore, √3/2=b/lSo,b=l√3/2=displacement.         ----------(2)From (1) and (2)Work done=mgl√3/2.              Ans.
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions