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`        A man weighing 60 kg is standing on a trolley weighing 240 kg.The trolley is resting on frictionless horizontal rails.If the man starts walking on the trolley along the rails at speed 1m/s,then after 4 seconds,his displacement relative to the ground will be`
2 years ago

Arun
23385 Points
```							Dear student

the trolley shall move backwards to conserve momentum. the back ward momentum would be shared by both the trolley and the man.
applying conservation of momentum
60*1 =  (240+60)*v
or
60 = 300 v
v = 1/5 m /sec
v = 0.2 m/sec
speed of man w.r.t ground = (1 – 0.2) m/sec
= 0.8 m/sec
displacement of man = 0.8 * 4 = 3.2 m

Regards
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions