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Grade: 12
        

A man walks 4m north then 3m towards east and there he climbs a pole of 12m height. What is the displacement?

 
9 months ago

Answers : (2)

Aditya
13 Points
							
Man walks 4m north , 3m east and  climbs 12 m can be written as 3i+4j+12k in xyz plane
Using formula for displacement of vector from origin,
Disp.=root
9 months ago
Vaidik sharma
15 Points
							
Answer = 13m
According to vector , the equation is exactly 4i + 3j + 12j , to find magnitude take root of 4^2 + 3^2 + 12^2  = 13 so the displacement is 13m
 
9 months ago
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