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A man walks 4m north then 3m towards east and there he climbs a pole of 12m height. What is the displacement?
Man walks 4m north , 3m east and climbs 12 m can be written as 3i+4j+12k in xyz planeUsing formula for displacement of vector from origin,Disp.=root
Answer = 13mAccording to vector , the equation is exactly 4i + 3j + 12j , to find magnitude take root of 4^2 + 3^2 + 12^2 = 13 so the displacement is 13m
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